PHYSICAL CHEMISTRY

I. KINETIC MOLECULAR THEORY: Ideal Gas

Assumptions for the establishment of Kinetic Molecular Theory

  • On Motion: The gas consists of molecules moving at random motion.
  • On Size: The volume of the particle is negligible compared to the volume of its container.
  • On Interaction: The spherical particles undergo brief, perfectly elastic collision.

 

A. Molecular Speed

v = \sqrt{\frac{3RT}{M}}                   M is Molar Mass

Example 1:
What is the average speed of the oxygen gas at T = 45 oC?
Solution:

v = \sqrt{\frac{3RT}{M}} = \sqrt{\frac{3(8.314)(45+273.15)}{\frac{32 }{1000 }}}      (Note: Division by 1000 of Molar Mass is to convert g to kg)
v = 497.988 \;\frac{ m}{s}

B. Kinetic Energy of a Particle

The assumption in KMT is that gas particles are spheres and therefore only exhibiting translational motion. Hence, the gas only possesses translational kinetic energy.

KE = \frac{3}{2}kT
k is Boltzmann Constant (Casio Calculator 991 #25); k = 1.3805 x 10-23 Joules/particle.K

 

Example 2:
What is the Kinetic Energy of an Argon molecule at T = 45 oC?
Solution:
KE = \frac{3}{2}kT
KE = \frac{3}{2}(1.3805 \times 10^{-23})(45 + 273.15)
KE = 6.59 \times 10^{-21} \;\frac{J }{particle}

C. Total Kinetic Energy of a Gas: Internal Energy

Kinetic Energy of a single particle multiplied by the total amount of particles.

KE_{T} = \frac{3}{2}(nR)T

Example 3:
Find the total kinetic energy of 3 moles of Argon at T = 45 oC.

Solution:

KE_{T} = \frac{3}{2}(8.31447) (45 + 273.15)
KE_{T} = 11,903.62 \;J

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